5y^2-4x^2=20

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Solution for 5y^2-4x^2=20 equation:


Simplifying
5y2 + -4x2 = 20

Reorder the terms:
-4x2 + 5y2 = 20

Solving
-4x2 + 5y2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5y2' to each side of the equation.
-4x2 + 5y2 + -5y2 = 20 + -5y2

Combine like terms: 5y2 + -5y2 = 0
-4x2 + 0 = 20 + -5y2
-4x2 = 20 + -5y2

Divide each side by '-4'.
x2 = -5 + 1.25y2

Simplifying
x2 = -5 + 1.25y2

Reorder the terms:
5 + x2 + -1.25y2 = -5 + 1.25y2 + 5 + -1.25y2

Reorder the terms:
5 + x2 + -1.25y2 = -5 + 5 + 1.25y2 + -1.25y2

Combine like terms: -5 + 5 = 0
5 + x2 + -1.25y2 = 0 + 1.25y2 + -1.25y2
5 + x2 + -1.25y2 = 1.25y2 + -1.25y2

Combine like terms: 1.25y2 + -1.25y2 = 0.00
5 + x2 + -1.25y2 = 0.00

The solution to this equation could not be determined.

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